integral from pie over two cos qubed(1/2x)sin(1/2x)dx

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1 Answer

J=∫cos3(½x)sin(½x)dx for x∈[0,π/2] (?)

Let u=cos(½x), so du=-½sin(½x)dx, and sin(½x)dx=-2du.

When x=0, u=1; when x=π/2, u=1/√2.

J=-2∫u3du=-½u4 for u∈[1,1/√2].

J=-½(¼-1)=⅜.

by Top Rated User (1.1m points)

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