f(x)=(x-1)^2-2 find the vertex, the y intercept and x intercept if any

Question

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Answer 1

?????????????? vertex ?????????????

aent no vertex...kerv is smooth...no pinty thangs...

its a parabola that kerv up

yu kan find the bottom bi get tangent & find weer tangent=0

y=(x-2)^2 -2

1 point is (0,-2), so kerv go belo x-axis

for big & negativ x, kerv go abuv x-azis, so it gotta kros x-axis at 2 point

dy/dx=2*(x-2)...this =0 at x=2, so that is the bottom av the parabola...(2,-2)