perpendicular to 4x + y = 8 through (4, 3)

Question

the answer is a equation.

Comments

any st line perpendicular to 4x + y = 8 is x-4y=k ,k=construction const. if it passes through (4,3),
4-4*3=k => k=_8.
so , read st line is  x-4y+8=0.

Answer 1

line thru point= (4,3)

90 deg tu line...y=-4x+konst

90 deg slope=+1/4=0.25

y=0.25x+konst

projejt line from x=4 tu x=0...deltax=-4

deltay=slope*deltax=0.25*(-4)=-1

y=3-1=2

point=(0,2)