find the equation of parabola with vertex at (-2,1)

IM CONFUSED AND DONT UNDERSTAND THIS AT ALL
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1 Answer

yu didnt sae if yu want parabola tu go out ("open') along x-axis or y-axis

(or sumthun els)

for horizontal axis: (y=y0)^2 =4a(x-x0)

vertex=(x0,y0)

a=distans from vertex tu fokus

yu sae vertex=(-2,1), so (y-1)^2=4a(x+2)
by

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