6(m-n)^2+22(m-n)-40 using substitution

Solve 6(m-n)^2+22(m-n)-40 using substitution
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set m-n=x & yu hav 6x^2 +22x -40=0 . . . or 3x^2+11x-20=0 . . . quadratik equashun giv x=1.3333333 or x=-5 . . . so m-n=-5
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