[2^(-1/2) * 3^(2/3)] / [2^(3/2) * 3(-1/3)]

how do I solve this? i got as far as 1^(-4/3)
in Algebra 2 Answers by

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1 Answer

me assume the last term shood be 3^-(1/3)

term1...2^-1/2=2/sqrt(2)=sqrt(2)

term2...2^2/3=1.5874010519681993

top=term1 * term2=1.4142135623 73095... *1.58740105...=2.244924096618746

term3...2^(3/2)=2^1.5=2.8284271247461903

term4...3^-(1/3)=1/kube root(3)=1/1.4422495703074083...0.6933612743541962

bottom=term3*term4=1.9611218356086166

top/bottom=1.144714242600897
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