How to Construct a triangle PQR, given that PR = 6.5 cm, angle P = 120 degree and PQ = 5.2 cm.

Question

the question is from the construction lesson.

Answer 1

yu giv 2 sides & 1 angel, so me assume angel tween the 2 sides

lengths=6.5 & 5.2

angel=120 deg

##### side3=10.15332

angels: 10.15332, 43.85378, 60 deg

area=14.63583, base=6.5, hite=4.5033333

rim-leng=21.85332

top point=(-2.6, 4.50333333)

inside serkel...radius=1.33946 & senter=(0.77333, 1.33946)

Answer 2

2667

Answer 3

1. Mark a point P.   Draw a circle centered at P with radius 5.2 cm.    From P, draw a ray rightwards crossing the circle P at Q (PQ=5.2 cm).   ΔPQR will be constructed above segment PQ.

2. From Q, draw an arc with radius PQ crossing the circle P at M above Q.    From M, draw an arc with the same radius, PQ, crossing the circle P at N above P.

3. From P thru N, draw a ray upwards.   From P, draw an arc upwards with radius 6.5 cm crossing the ray at R above N.   Connect R to Q.

4. Done.   We have ΔPQR with PR=6.5 cm, PQ=5.2 cm and ∠P=120 degree.