where do y=x^2-4x-1 and y+3=-x intersect

Question

where do they intersect if they are drawn on the same set of axes

Answer 1

y=x^2 -4x -1 = -x-3

x^2 -3x+2=0

quadratik equashun giv zeroes:

x=1 or 2

Answer 2

Look at the answer above....

and then, plug each x from the previous answer into one of the equations to find y.

x=1; y=1^2-4-1=-4  So, first point of intersection is: A(1;-4)

x=2: y=2^2-8-1=-5 The second point is: B(2;-5)