Write the number as a sum: 100a+10b+c, where a is the digit in the 100s, b the digit in the 10s and c the units. If a=10b, then, unless a and b are both zero, there are four digits in the number. But it says that b is greater than 8, so a must be greater than 80. Also, b must be 9 because they are no more digits greater than 8. The number must end 0, 2, 4, 6 or 8 to be even. The possibilities are 9090, 9092, 9094, 9096 and 9098. If 0 is not a digit but a placeholder, then the number has three digits and 9090 is not a possibility leaving us with the last four numbers.