Maximum and Minimum value of algebraic expression.solve with detail steps sir/mam.
in Word Problem Answers by Level 1 User (580 points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Consider the expression ab+bc+cd. If a and d were zero then b+c=1, so let b=c=1/2. Then the expression=1/4. Note that b and c appear twice: b in ab and bc, and c in bc and cd, while a and d appear only once each. Therefore b and c contribute more to the sum than a and d. Although none of the quantities can be zero, a and d can be sufficiently close to zero so that the expression approaches 1/4. If b=1/2-x and c=1/2+x then bc=1/4-x^2 so the product is always <1/4. If b=1/2-x and a=x, and c=1/2-x and d=x, where x is very small and positive, a+b+c+d=1. The expression becomes: 2x(1/2-x)+1/4-x+x^2=x-2x^2+1/4-x+x^2=1/4-x^2. Therefore the maximum value is <1/4, but x can be made infinitesimally small. This makes the maximum 0.25.

Example: x=1/100: a=d=0.01; b=c=0.49; expression=0.0049+0.2401+0.0049=0.2499.

Example: x=1/1000: expression=0.249001+2*0.000499=0.249001+0.000998=0.249999.
 

by Top Rated User (1.1m points)

Related questions

1 answer
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,542 questions
99,804 answers
2,417 comments
522,521 users