the diagram shows four towns,A,B,C and D.C is 110km due East of A.ABC=90 and AB=70km.calculate the distance BC and the bearing of B from A

Question

please help me to answer this question step by step

Answer 1

The picture shows the given information. Since ABC is a right triangle, AB^2+BC^2=AC^2.

So BC^2=√(110^2-70^2)=√7200=60√2=84.8528km.

The bearing of B from A=BCA, because the vertical angle has the same measure as BCA (supplementary angles). sinBCA=70/110, so the bearing is 39.5212 degrees from North.