please help me with the answer before 12pm please
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

When the centre of the ellipse is at (h,k), then the standard equation of the ellipse is:

((x-h)^2)/a^2+((y-k)^2)/b^2=1, where a and b are the lengths of the semi-major and semi-minor axes. The foci lie along the major axis, which must be at y=-6, since -6 is the shared coord for the two foci. The average of the x coords for the foci is (2+8)/2=5. This indicates where the centre of the ellipse is: (5,-6) so h=5 and k=-6. The distance f between the centre of the ellipse and the foci is given by f^2=a^2-b^2, so a^2-b^2=(5-2)^2=(8-5)^2=9. The major axis has length 10, so ther semi-major axis, a, has length 5. Therefore we can find b: 25-b^2=9, so b^2=16, b=4.

The equation of the ellipse is (x-5)^2/25+(y+6)^2/16=1.

by Top Rated User (1.1m points)

Related questions

1 answer
asked May 6, 2013 in Algebra 2 Answers by anonymous | 1.1k views
1 answer
asked Mar 26, 2013 in Calculus Answers by anonymous | 1.3k views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,542 questions
99,804 answers
2,417 comments
522,561 users