The figure shows the distance of a car from a measuring position located on the edge of a straight road.

Question

(a) What was the average velocity of the car from t=10 to t=30 seconds?

(b) What was the average velocity of the car from t=20 to t=25 seconds?

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Answer 1

(a) Including the period where the car is stationary, the average velocity is (300-100)/(30-10)=200/20=10 ft/sec.

(b) average velocity = (100-200)/(25-20)=-100/5=-20 feet/sec.