The center is at (1,-1), Transverse axis is parallel to x-axis; Length of latus rectum is 9, distance between directrices = 8sqrt13/13
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The center is at (1,-1), Transverse axis is parallel to x-axis; Length of latus rectum is 9, distance between directrices = 8/√(13)

d = a^2/c  => 2d = 2a^2/c = 8/√(13)   (d is distance of one directrix from centre)

p = b^2/a  => 2p = 2b^2/a = 9     ( p is semi-latus rectum)

A basic relation between semi-major axes, a and b, and c, eccentricity is b^2 = c^2 – a^2

Using b^2 = c^2 – a^2 and the previous two equations,

b^2 = c^2 – a^2  => 9a = 2b^2 = 2c^2 – 2a^2

using a^2 = 4c/√(13),  =>  c^2 = 13a^4/16

Therefore, 9a = 13a^4/8 – 2a^2

13a^4 – 16a^2 – 72a = 0

13a^3 – 16a – 72 = 0      (since a ≠ 0)

This factorises as,

(a – 2)(13a^2 + 26a + 36) = 0

Only 1 real root: a = 2

From c^2 = 13a^4/16  => c^2 = 13,  c= √(13)

From 2a^2 = 8c/√(13) = 8  a^2 = 4,   a = 2     (confirmation)

From b^2 = c^2 – a^2,   =>  b^2 = 13 – 4 = 9,  b = 3

Eqn of ellipse

x^2/a^2 – y^2/b^2 = 1

x^2/4 – y^2/9 = 1   (Centred at (0,0))

or,

(x – 1)^2/4 – (y + 1)^2/9 = 1    (Centred at (1,-1))

by Level 11 User (81.5k points)

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