If the sides of a square measure 10√6 units, then find the length of the diagonal.

Question

Please answer. Thank you

Answer 1

By Pythagoras diagonal = √(10√6)²+(10√6)² = √600+600 or 10√6+6 = 10√12 = 10√4×3=10×2√3=20√3=34.64 units.

Answer 2

if the side oof a square is a units then the length of its diagonal is d=asqrt(2)

in our case we have a=10sqrt(6)  so the diagonal will be 10sqrt(6)sqrt(2) =====>> 10sqrt(12)

or 10sqrt(3*4)  ===>>> 10*2sqrt(3)  ====>>> 20sqrt(3) and since sqrt(3)=1.732 approx.

the diagonal will be 20*1,732 = 34.64 units approx