how to i graph and find the vertex and axis of symmetry of y=x^2+2

Question

I need to write the equation of the axis of symmetry and find the coordinates of the vertex of the graph of each function. Identify the vertex as a maxismum or minimum and the graph the function.

y=x^2+2

Answer 1

y=x²+2 is a parabola and has a minimum value of 2 when x=0 so the vertex is (0,2) and the axis of symmetry is x=0, which is the y-axis. The graph is U-shaped with the centre of the U located at (0,2). By plotting a few values you can get a good idea of the spread of the arms, remembering that the axis of symmetry is like a mirror, so the parabola’s shape is reflected in the y-axis. The following points will help you to plot the graph: (-2,6), (-1,3), (1,3), (2,6).