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1 Answer

N=pq=221=13×17.

(p-1)(q-1)=12×16=192.

e=5 (encryption exponent).

The decryption exponent is d, such that:

de=1 mod (p-1)(q-1):

5d=1 mod 192.

5d=192m+1,

When m=2, 5d=385, decryption factor d=77; 5×77=1 mod 192.

Plaintext=Cᵈmod N = C⁷⁷ mod 221.

For decrypted Tfg, T=64+20=84, f=96+6=102, g=103.

So C=84⁷⁷ mod 221.

b=84, e=77=115₈=1001101.

The next step is to use modulo exponentiation and to apply d to decrypt each letter.

 

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