Geometry

Question

In the diagram given RQ||TU, angleTUS =72°, angleUSQ =128°and angle SQW =x. Find x.

Comments

No diagram provided!

Answer 1

In the diagram TÛS=72°, UŜQ=128°, SQ̂W=x° according to the question. Since no diagram was included in the question, I have guessed what it might look like.

TÛS=SŴQ=72°, angles on either side of the transverse between two parallel lines TU and RQ.

UŜQ is the exterior angle to triangle SQW, so SŴQ+x=128, making x=128-72=56°.