what is x? find m<NMO please!
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3 Answers

m< NMO
= m< LMN - m< LMO
= (5x - 23) - (x + 32)
= 5x - 23 - x - 32
= 4x - 55

Since <LMN is bisected, we have:

m< LMO = m< NMO
x + 32 = 4x - 55
4x - x = 32 + 55
3x = 87
x = 87 / 3
x = 29

Hence, we have:

m<NMO
= 4x - 55
= 4(29) - 55
= 116 - 55
= 61 degrees
by
m<1=(x-39)

m<2(x+61)
by
m<PMN and m<LMN
by

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