The formula for x is -b/2a so your problem is x^2 +8 because x*x is x^2 and 4*2=8. The formula for a quadratic equation is ax^2+bx+c and you don't have a b so your b is 0. -0/2(1) =0. Your axis of symmetry equation is x=0. If you want to graph as well, then you plug it into a graph... my teacher has us put three x-intercepts on either side so you would have -3,-2,-1,0,1,2,3 as your x-intercepts. Then you plug each one back into the original equation and those are your y's. They should be the same numbers on either side of the vertex- so if one coordinate is (-3,2), your other coordinate should be (3,2.) Hope this helps!