Can you solve 6/2(2+1) for me?

Question

wondering do i do distributive property first... and end up with the answer 1 or do i follow pemdas and get the answer of 9

Answer 1

well....this is time 11 for same quesshun,

but yu add sum werds tuit...

tu foers anser tu be 1, yu gotta du parts in differ order

That meen yu gotta add symbols tu foers it in the order yu want

6/2(2+1)

standard order: gotta du (2+1) first, so yu get 6/2*3

Then from left tu rite...6/2=3, then 3*3=9

Tu get anser=1, gotta get 6/6

that meen 6/2/(2+1)

or 6/ [2*(2+1)]

Answer 2

6/2(2+1) 2(2+1)= 6 6/6= 1

Answer 3

PEMDAS!!

6/2=3 and 1+2=3

3(3)=9

Answer 4

Problem: Can you solve 6/2(2+1) for me?

Note: this is not 6 divided by (2 times the quantity (2 + 1)). It is 6/2 times the quantity (2 + 1).

It doesn't matter whether you solve each part first, giving 3 * 3, or multiply each number in parentheses by 6/2, you get the same answer.

(6/2) * (2 + 1) = ((6/2) * 2) + ((6/2) * 1) = (3 * 2) + (3 * 1) = 6 + 3 = 9

Or

(6/2) * (2 + 1) = 3 * 3 = 9

 

There is no possible way to get 1 from this problem.