????????????? maebee that is spozed tu be
(x^2 -1) / abs(x-1)
yu sed x^2 -[1/abs(x-1)]
watch out for x=1...yu divide bi 1
maen thang abs(x) du is make symmetrik graf...left side hav same y as rite side
But this won hav komplikashuns for -1 <= x <=+1
& av koers, make shuer yu hav rite equashun