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1 Answer

i^-86785479=<br />

<br />

&nbsp;(1/i ) ^86785479=<br />

<br />

(1^86785479)/(i^86785479) =<br />

<br />

1/(i^86785476+3)=<br />

<br />

1/ ((i^86785476)*(i^3) ) <br />

<br />

1/ ((i^(21696369*4))*(i^3) ) <br />

<br />

1/ ( ( (i^(4))^21696369)*(i^3) ) = /////i^4=1 <br />

<br />

1/ ((1^21696369 )*( i^ 3))= /////////i^3 =-i<br />

<br />

1/ (1*(-i) )=<br />

<br />

1/ -i ///////// multiple 1 and -i by i <br />

<br />

1*i/-i *i=<br />

<br />

i/-i^2= ///////// i^2=-1<br />

<br />

i/-(-1)=<br />

<br />

i/1=<br />

<br />

i
by Level 1 User (620 points)
edited by

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