the equation of this quadratic function shown is of the form y=(x-a)^2+b. write down its equation?

The parabola has a given root which is the axis of symetry (-2,-3)
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Axis of symmetry is x=-2. The vertex is on this axis and it appears that the vertex is at (-2,-3). This makes a=-2 and b=-3, and y=(x+2)^2-3=x^2+4x+4-3=x^2+4x+1.

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