solve an show all work

Question

The width of the rectangle is twice its length. If the perimeter is at most 72 cm, what is the greatest possible value for its length?

A; write the formula for perimeter.

 B; write the algebraic equation for this problem

 C: solve the problem from part b

 D:  answer the question in the problem( label your work)

 Show all your work

Answer 1

A: the permeter of a rectangle (the area around) is length + length + width + width or simply 2L+2W = P

b: since you already know the width is 2 times the length the w=2L substitute that into the equation

2L+2(2L) = 72

2L+4L = 72

combin like terms

6L = 72

c: divide each side by 6

L = 12

d: length is 12 width is 24

2(12) + 2(24) = 72 (it checks out)

greatest possible value for length is 12