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hello guys...i need help with this question.....answer in detail.... luc, mark and lolly bought a ferrari. luc paid 1/7. of the total cost while mark paid 2/3 of what was remained. lolly paid sh28000. what was the price of the ferrari?
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If the total price of the Ferrari is "X",

what luc paid whas 1/7 of the price (total cost), which is x*1/7 or x/7

what mark paid was 2/3 from the remaining. The remaining is x*6/7 (because x-x/7=6x/7) and he paid 2/3 of it so .. its x*2/3*6/7 = x*12/21 or 12x/21

and lolly paid 28000

When you sum up the three of them you get the total price, which is X.

x/7 + 12x/21 + 28000 = x

3x/21 + 12x/21 +  588000/21 = 21x/21

15x+588000=21x

21x-15x=588000

6x=588000

x=98000

So the price of the ferrari was sh98000
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