Length of a rectangle=6ft long than twice the width. perimeter=102 ft. find the length and width

Question

Need to find the length and width of the rectangle

Answer 1

Call length L and width W. 6 ft longer than twice the width is 2W+6. Perimeter is 2L+2W=102. L=2W+6 so we substitute this in the perimeter equation: 4W+12+2W=102, so 6W+12=102, and 6W=90. Therefore W=15 and L is twice this plus 6 feet=36. Check the perimeter: 2*36+2*15=72+30=102. Checks out!

Answer 2

????????? maebee yu shood sae:

1. leng=2*wide+6,

2. rim-leng=102 ????????

leng+wide=rim-leng/2=51

(2*wide+6) +wide=51

3*wide+6=51

3*wide=45

wide=15

leng=2*wide+6=36