please help me ASAP
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me assume yu want a rite triangel with hite=20 & diagonal=80

80^2 -20^2=quuare av base leng

b^2=6400=400=6000

base=sqrt(6000)

base=77.45966692 ft

or bout 77.46ft

Or yu kan just yuze the invers sine(20/80)=sine-1(1/4)

invers sine(0.25)=14.477512185924283 deg

or bout 14.48 deg
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