what is the indefinite  integral of 1+3x
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The integral of  1+3x

So, when you integrate you 'add one to the power and then divide by the new power' (don't worry, i know this probably doesn't sound like it makes much sense)

Take an example,  The integral of  x^n = (x^(n+1))/(n+1)  + C  ,    (Or, in words, the integral of x to the power of n equals x to the power of n plus one all divided by n plus one plus C)    ,   where 'n' is any number  and  C is a constant (i.e. a number that we don't know).

So, for your equation 1 + 3x you can say that:

1 + 3x = 1x^0 + 3x^1 

So when you integrate this it becomes:

(1x^1)/1 + (3x^2)/2 + C = x + (3/2)x^2 + C

 

 

by Level 5 User (10.2k points)

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