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evaluate (d)/(dx) ((x^(2)-cos x)) / (sin x+8x)
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1 Answer

Let u=x2-cos(x), du/dx=2x+sin(x).

Let v=sin(x)+8x, dv/dx=cos(x)+8.

(d/dx)(u/v)=(vdu/dx-udv/dx)/v2=

((sin(x)+8x)(2x+sin(x))-(x2-cos(x))(cos(x)+8))/(sin(x)+8x)2.

So (d/dx)((x2-cos(x))/(sin(x)+8x))=

((sin(x)+8x)(2x+sin(x))-(x2-cos(x))(cos(x)+8))/(sin(x)+8x)2.

Expanding these terms:

(sin2(x)+10xsin(x)+16x2-(8x2+x2cos(x)-8cos(x)-cos2(x)))/(sin(x)+8x)2,

(sin2(x)+cos2(x)+8x2-x2cos(x)+10xsin(x)+8cos(x))/(sin(x)+8x)2,

(1+8x2-x2cos(x)+10xsin(x)+8cos(x))/(sin(x)+8x)2.

So (d/dx)((x2-cos(x))/(sin(x)+8x))=

(1+8x2-x2cos(x)+10xsin(x)+8cos(x))/(sin(x)+8x)2.

by Top Rated User (1.1m points)

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