Question

What are the dimensions of a rectangle whose perimeter is 54 cm and area is 500 cm squared?

Answer 1

rektangel

area=500

rim-leng=54, so half-rim=27

leng+wide=27    or leng=27-wide

leng*wide=500

(27-wide)*wide=500

-wide^2 +27wide -500=0

or wide^2 -27wide +500=0

BIG PROBLEM...zeros=komplex numbers

if yer rektangel=square, leng=wide=root(500)=22,2595

& rim-leng=4*22.2595=89.443

yer rim-leng=54 is 2 small