Question

The angle of elevation of a jet fighter from a point A on the ground is 600 . After a flight of 15

seconds, The angle of elevation changes to 30◦. If the jet is flying at a speed of 720km/ hr, find the

constant height at which the jet is flying.

Answer 1

assume plane fli at konstant speed & altitude

speed:720,00 meter/3600 sek=200 meter/sek

200*15=3,000 meters in 15 sek

Hite=tangent(angel)

If angel dekreez, plane fli awae

look at it from the aerplane...his angel chaenj from 30 deg tu 60 get

triangel side on ground gro bi 200 meters

hite *tan(30deg)=x

then hite *tan(60 deg)=x+200

hite*[tan(60) -tan(30)]=200

tan(30)=0.577350269

tan(60)=1.732050808

tan(60) -tan(30)=1.154700539

hite=200/1.1547

hite=173.205