For the following hypothesis testing questions, be sure to include the claim, null and alternative hypothese, test statistics, graph, critical values or P-value, reject or fail to reject null hypothesis, and a summary statement of the conclusion in non-technical terms. Assume all samples come from populations that are normailly distributed.

 

9) An article in a national journal reports that 34% of American fathers take no responsibility for child care. A statistics student doesnt agree with this percentage, and claims the tru percentage is less than 34%. She decides to conduct a test and samples 285 fathers from her hometown of Waconia. She discovers that 80 do not take responsibility for child care. Using 0.01 level of significance, test the students claim.
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We only have the mean proportion of 34%, and no standard deviation has been given. Let's assume that the standard deviation is 0.5%, implying that the proportion is 34±0.5%. In the test sample the proportion is 80/285=28% approx. 

H0: μ=34%; Ha: μ<34%, so we do a 1-tailed test (one-sided test). Z=(28-34)/0.5=-12, corresponding to p=0 or thereabouts, which is well in excess of the critical value for 1% significance (Z=2.58). It's clear that without a given standard deviation we conclude that Hmust be rejected so it's more likely that the proportion is, in fact, lower than 34%. If 6/σ>2.58, that is, only if the population standard deviation, σ<6/2.58, σ<2.3%, can H0 be rejected. In this case the journal should have stated the proportion as 34±2.3%, that is, between 31.7% and 36.3%. If σ>2.3%, His more likely to be true.

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