4x^2+x-3y-8=0, sketch the graph.

How to find the center (h,k) and the value of a and b?
in Geometry Answers by Level 1 User (220 points)

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3y=4x^2 +x -8... y=(4/3)x^2 +x/3 -(8/3)... dy/dx=(8/3)x +(1/3) zero at x=-1/8...lo av the parabola parabola with vertikal axis, kerv go up, bottom at (-1/8), -7.926)
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