from the point on horizontal ground a surveyor measures the angle of elevation of the top of a flagpole as 18 degree. he moves 50 metre near to the flagpole and measure the angle of elevation as 26 degree . determine the height of the flagpole
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Let the distance from the pole be x. The height of the pole we'll call h.  So h/x=tan18; h/(x-50)=tan26 after he moves 50m nearer to the pole. x=hcot18, so we can write h/(hcot18-50)=tan26. This is an equation with only one unknown, h. So h=(hcot18-50)tan26, h(cot18tan26-1)=50tan26=24.3866 approx. and h=24.3866/0.5011=48.6675m approx.

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x=149.783 approx and h/x=tan18. x-50=99.783 and h/99.783=tan26

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