Math problem

Question

we're learning linear programming and this is the problem (i know the answer but i don't know how to get to it, i fell like we don't have enough info about problem) (answer: 560€, 560 donuts and 280 water bottles) John sells donuts and water. The mass of the donut is 0.125 kg, and the water is 0.5 kg. John must have at least 80 donuts and 60 bottles of water every day. For the two donuts sold, John sells two bottles of water. The profit is 80 cents per donut, and 40 cents per bottle of water. How many donuts and bottles of water should John sell to achieve the highest possible profit?

Comments

"For the two donuts sold, John sells two bottles of water" doesn't seem to fit the known solution, and the solution implies that there is one bottle of water sold for every two donuts. Please review, revise and resubmit your question. The question also includes the weights of the donuts and water bottles, which seems irrelevant because the profit is measured in euros not kilograms. The profit on each donut and each bottle of water seems to be rather high, suggesting that perhaps the item profit is based on weight rather than on the individual items.

No upper limiting constraints have been applied, which implies an open-ended solution with no limit to the daily profit, which would only depend on how much he can sell. Also, constraints are normally inequalities, and here we have an equality (two donuts and two bottles of water specifically).

Answer 1

See comment on question.

Note that 560 donuts weigh 70kg, so there may be some upper limits on how much John can sell in a day based on weight. Similarly for water bottles. 280 bottles weigh 140kg, according to the given information.

As it stands, this question can't be answered meaningfully.